1.6x^2+5x+3.5=0

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Solution for 1.6x^2+5x+3.5=0 equation: 



1.6x^2+5x+3.5=0

a = 1.6; b = 5; c = +3.5;
Δ = b2-4ac
Δ = 52-4·1.6·3.5
Δ = 2.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{2.6}}{2*1.6}=\frac{-5-\sqrt{2.6}}{3.2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{2.6}}{2*1.6}=\frac{-5+\sqrt{2.6}}{3.2}
$

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